5^(z+1/3)=25^(1/z)

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Solution for 5^(z+1/3)=25^(1/z) equation: 



5^(z+1/3)=25^(1/z)

We move all terms to the left:

5^(z+1/3)-(25^(1/z))=0



Domain of the equation: z))!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

5^(+z+1/3)-(25^(+1/z))=0

We calculate fractions


(5^(+2z)))/3*z)))+()/3*z)))=0



We calculate terms in parentheses: +(5^(+2z)))/3*z)))+()/3*z))), so:

5^(+2z)))/3*z)))+()/3*z))

We can not solve this equation

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